800-10(240)+.25(240)^2=x

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Solution for 800-10(240)+.25(240)^2=x equation: 



800-10(240)+.25(240)^2=x

We move all terms to the left:

800-10(240)+.25(240)^2-(x)=0

We add all the numbers together, and all the variables

-1x-9439.93629424=0

We move all terms containing x to the left, all other terms to the right

-x=9439.93629424

x=9439.93629424/-1

x=-9439+0.93629424/1

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